Sheet Metal Flat Pattern Calculator

A flat pattern is the blank you cut before anything is bent. It is never the sum of the finished dimensions, because each bend swallows some material. This calculator develops the blank length for a part with any number of equal bends, working either from outside mould-line dimensions (subtracting a bend deduction per bend) or from tangent-to-tangent flat segments (adding a bend allowance per bend). It shows both routes so you can cross-check the layout, and reports the blank area once you enter a width.

Calculator

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Inputs this calculator takes, with typical values
InputWhat to enterExample
Sum of the dimensions along the unfoldAdd up every leg dimension in the direction you are unfolding, using the basis selected below.8 in
Dimensions are measuredOutside mould line is how most fabrication prints are dimensioned; tangent to tangent is what a CAD flat measures.To the outside mould lines
Number of bendsCount only the bends that lie along the direction you are unfolding.2
Material thicknessMeasure the sheet rather than reading the gauge chart.0.0625 in
Inside bend radiusThe radius the tooling actually produces, roughly 16 percent of the V-die opening when air bending.0.0625 in
Bend angle (angle turned through)Every bend is treated as having this same angle; a square corner is 90.90 °
K-factorNeutral axis position as a fraction of thickness, best measured from a test bend.0.42
Blank widthDimension across the bend lines, used only to report the blank area.6 in

It returns

  • Flat blank length — Cut the blank to this length in the unfold direction.
  • Flat blank length
  • Bend allowance per bend
  • Bend deduction per bend
  • Total adjustment applied — Difference between the entered dimension sum and the developed length.
  • Blank area

The formula

Lflat=outsidednBD
BD=2tan(A2)(R+T)BA

In plain text: L_flat = Σ outside dims − n × BD = Σ flat segments + n × BA

  • L_flatDeveloped blank length in the unfold direction (in or mm)
  • dEach leg dimension along the unfold (in or mm)
  • nNumber of bends crossed by the unfold (count)
  • BABend allowance, (π/180)·A·(R + K·T) (in or mm)
  • BDBend deduction, 2·OSSB − BA (in or mm)

The two forms are algebraically identical because each outside dimension exceeds its flat segment by one setback, and each bend contributes two setbacks.

Updated Category Sheet Metal Bending & Forming Verified against published test cases Reading time 11 min

What a flat pattern is and why it is shorter than the part

The flat pattern is the two-dimensional blank a bent part came from. Cut it, form it on the brake, and the finished dimensions land where the drawing says. Get it wrong and every downstream feature moves — holes shift relative to bend lines, flanges finish long or short, and an enclosure stops closing.

The reason the blank is not simply the sum of the finished legs is that each bend consumes material. Inside the bend the metal compresses and outside it stretches, and only one surface through the thickness keeps its original length. The arc of that surface is the bend allowance, and it is always shorter than the path around the outside of the corner. Dimension a part to its outside mould lines and you are measuring to imaginary sharp corners that the real bend never reaches, so you must subtract a bend deduction for each bend.

Every bend crossed by the unfold contributes one deduction. A simple L has one, a U-channel has two, a hat section has four, and a box formed from a single blank has bends in both directions — unfold each direction separately, because a bend that runs parallel to the direction you are measuring does not consume any length in that direction.

Two routes to the same blank, and why they agree

Which formula you use depends on how your print is dimensioned, not on the part.

From outside mould lines. Most fabrication drawings dimension to the outside corners, which is what a caliper on the finished part measures. Add up those dimensions and subtract one bend deduction per bend: L = Σdoutside − n × BD.

From tangent-to-tangent flats. A CAD flat pattern, or a layout measured to where each flange stops and the radius begins, gives you the straight segments only. Add one bend allowance per bend: L = Σdflat + n × BA.

These are the same equation. Each outside dimension exceeds its neighbouring flat segment by exactly one setback, OSSB = tan(A/2) × (R + T), and each bend sits between two dimensions, so it adds two setbacks to the outside sum. Since BD is defined as 2 × OSSB − BA, subtracting BD from the outside sum removes those two setbacks and puts the allowance back. That identity is the best check you have: develop the same part both ways and the answers must match to the last decimal. If they do not, one of the two dimension sums was taken on the wrong basis.

Two special cases fall out. At 180° the outside faces are parallel, the setback is infinite, and the outside basis simply does not exist — a hem must be developed from flat segments. And at shallow angles with generous radii the deduction turns negative, which means the blank has to be longer than the sum of outside dimensions. Both are real geometry, not errors.

Worked example: a U-channel in 1/16 in steel

The drawing calls for a channel 4.000 in wide with 2.000 in legs, all dimensions to the outside, in 0.0625 in steel bent to a 0.0625 in inside radius. The shop has measured K = 0.42 on this tooling.

  1. Sum the outside dimensions. 2.000 + 4.000 + 2.000 = 8.000 in, across two bends.
  2. Bend allowance. R + K·T = 0.0625 + (0.42 × 0.0625) = 0.08875 in. BA = 1.5707963 × 0.08875 = 0.139396 in.
  3. Setback. tan(45°) = 1, so OSSB = 1 × (0.0625 + 0.0625) = 0.125 in.
  4. Bend deduction. BD = (2 × 0.125) − 0.139396 = 0.110604 in.
  5. Develop. 8.000 − (2 × 0.110604) = 7.778791 in.

Cross-check on the other basis. Each 2.000 in leg loses one setback, giving 1.875 in of flat; the 4.000 in web loses a setback at each end, giving 3.750 in. Total flat = 1.875 + 3.750 + 1.875 = 7.500 in. Add two allowances: 7.500 + (2 × 0.139396) = 7.778791 in. The two routes agree exactly, which confirms both the arithmetic and the dimension basis.

To lay out the bend lines on the blank, work from one edge: the first tangent line falls at 1.875 in, the bend occupies 0.139396 in of arc, the web flat runs to 1.875 + 0.139396 + 3.750 = 5.764396 in, and the second bend ends at 5.903791 in, leaving the final 1.875 in leg. Those are neutral-axis positions on the flat blank, which is what a laser or turret program needs for scribe lines.

Reading the result and checking it before you cut

The developed length should always be shorter than the sum of outside dimensions on ordinary bends, and the shortfall should be roughly 0.4 to 0.5 times material thickness per 90° bend for radii near one thickness. If your deduction is far outside that band, one of the inputs is wrong — most often the inside radius, because it is set by the die opening rather than the punch, or the angle, because someone entered the included angle instead of the angle turned through.

Scale is the second sanity check. On a 20-gauge part the total adjustment across four bends is under 0.15 in, which many shops would absorb in trimming. On 1/4 in plate the same four bends move the blank by nearly 1.8 in, and no amount of trimming rescues a blank cut without it. Thickness is the dominant driver, and it enters twice — once directly in the setback and once through the K-factor offset.

The blank area output is there for nesting and cost. Multiply by density to get the weight of the blank, which is what a supplier quotes against; the steel plate weight calculator does that step and also converts to pounds per square foot.

Finally, remember what this calculator assumes: all bends share one angle, one radius and one K-factor. Real parts often mix a tight 90° corner with an open 30° break. When they do, compute the allowance for each distinct bend in the bend allowance calculator and add the results by hand, rather than averaging.

Bend deduction per 90° bend, R = T, K = 0.42

Multiply the per-bend figure by the number of bends and subtract from the sum of outside dimensions. Values are BD = 4T − 1.5707963 × 1.42T = 1.769470 × T.
MaterialThickness (in)Bend allowance (in)Bend deduction (in)Total for 4 bends (in)
20 ga steel0.03590.080080.063520.25410
18 ga steel0.04780.106620.084580.33832
16 ga steel0.05980.133390.105810.42326
14 ga steel0.07470.166620.132180.52872
12 ga steel0.10460.233310.185090.74035
1/16 in0.06250.139410.110590.44237
1/8 in0.12500.278820.221180.88474
3/16 in0.18750.418220.331781.32710
1/4 in0.25000.557630.442371.76947

Only valid at 90 degrees with the inside radius equal to thickness and K = 0.42. Change any of those and recompute; the numbers do not scale across angles.

Layout mistakes that scrap blanks

  • Mixing dimension bases in one sum. Two legs measured to the outside and one to a tangent line produces a blank wrong by one setback. Pick a basis, convert everything to it, then compute.
  • Counting bends that do not lie along the unfold. Only bends crossed by the direction you are developing consume length in that direction. Unfold length and width separately.
  • Using a nominal gauge thickness. Sheet is supplied to a tolerance, and thickness drives both the setback and the K-factor offset. Micrometer the coil.
  • Taking the inside radius from the punch. In air bending the radius comes from the die opening, roughly 16% of it in mild steel. A sharp punch in a wide die still gives a large radius.
  • Applying one K-factor to a part that mixes radii. K depends on the R/T ratio. A part with one tight bend and one generous bend needs two allowances, computed separately.
  • Forgetting hole-to-bend distance. A hole closer to the bend line than about 2.5 times thickness plus the radius will distort. The flat pattern positions it correctly; the process still deforms it.

How this sits alongside CAD and the press brake

Every CAD system implements this same geometry. SolidWorks, Inventor and Solid Edge all let you specify K-factor, bend allowance or bend deduction per bend, and a bend table is just a lookup of the same quantities indexed by thickness and angle. When a CAD flat and a hand calculation disagree, the cause is almost always a different K-factor or a different inside radius carried in the sheet metal style — not a different formula. Comparing the two is a fast way to audit what your CAD template actually assumes.

Upstream of the layout sits the question of whether the bend can be made at all. The die you pick fixes both the achievable radius and the force, and the press brake tonnage calculator reports the radius that a given V-die produces along with the tonnage and the shortest flange the die will hold. Work in that order: choose the die, read the radius, then develop the blank. Choosing a radius first and finding no die produces it is the usual sequence error.

Downstream, the blank feeds cutting and material planning. Once you know the developed length and width, the metal weight calculator and plate weight calculator turn the blank into pounds for quoting and freight. If the part is structural rather than enclosure sheet, the strength of the formed section is a separate question — forming does not change the material, but it does work-harden the bend zone, which a tensile check on the flat material will not capture. The stress and strain calculator covers the elastic behaviour of the parent material.

One older convention is worth recognising. Aircraft sheet-metal practice often uses a setback table and a fixed bend-allowance chart rather than a K-factor, and some shops still work in the Y-factor, which equals K × π/2 and folds the radian conversion into the constant. Both encode the same neutral-axis assumption; the K-factor form simply exposes the empirical part so you can measure it.

Frequently asked questions

How do I calculate the flat blank length for a U-channel?

Add the three outside dimensions and subtract two bend deductions. For a 4 in web with 2 in legs in 1/16 in steel at a 1/16 in radius and K = 0.42, the deduction is 0.1106 in per bend, so the blank is 8.000 − 0.2212 = 7.7788 in. If your dimensions are tangent-to-tangent rather than outside, add two bend allowances of 0.1394 in to a 7.500 in flat sum instead — the answer is the same.

Should I use bend allowance or bend deduction?

Match the one your dimensions use. Bend deduction goes with outside mould-line dimensions, which is how most fabrication prints are drawn and how a caliper measures a finished part. Bend allowance goes with tangent-to-tangent flat segments, which is what CAD reports and what a layout scribed on the blank uses. Both give the same blank; mixing them in one sum does not.

What if my part has bends at different angles?

Compute each bend separately and add the results. This calculator applies one angle, radius and K-factor to every bend, which covers channels, hats and boxes with uniform corners. For a mixed part, run the single-bend numbers in the bend allowance calculator for each distinct combination, sum the allowances or deductions, and apply that total to your dimension sum.

Does the blank length change if I bend in a different order?

No. Developed length is a property of the geometry, not the sequence. Bend order matters for accessibility, for whether a flange collides with the ram, and for how tolerances stack across the part, but the amount of material consumed by each bend is fixed by angle, radius, thickness and K-factor. Plan the sequence for clearance and gauging, then cut the blank the calculator gives you.

Why is my blank longer than the sum of the outside dimensions?

Because the bend deduction went negative, which happens on open bends with a generous inside radius. When the bend allowance exceeds twice the setback, the deduction flips sign and the developed length exceeds the dimension sum. It is a real result. If you did not expect an open bend, check that you entered the angle turned through rather than the included angle.

How do I lay out the bend lines on the blank?

Work from one edge, adding each flat segment and each bend allowance in order. On the worked example the first tangent line sits at 1.875 in, the arc occupies 0.1394 in, the web runs to 5.7644 in, and the second bend ends at 5.9038 in. Note that these are tangent positions on the flat; press brake back gauges are usually set to a flange dimension measured to the part edge, so check your machine's convention before transferring numbers.

Can I develop a box from a single blank with this?

Yes, but run it twice. Unfold the length direction with the bends that cross it, then unfold the width direction with its own bend count. Bends running parallel to the direction you are measuring consume no length in that direction. Corner relief notches then have to be added at the intersections, sized to the radius plus thickness so the two bends do not fight each other.

How accurate is this compared with a test bend?

As accurate as the K-factor you feed it, and no more. The geometry is exact; the neutral-axis position is empirical. A K-factor taken from a chart typically lands within a few thousandths of an inch per bend on common gauges, which is fine for enclosure work and marginal for close-tolerance assemblies. Back-solving K from one measured test bend on the actual tooling removes most of the error.

References

  • Machinery's Handbook, 31st Edition — Sheet Metal Working — Industrial Press
  • Sheet Metal Forming Processes and Die Design, 2nd Edition — Industrial Press
  • Manufacturers' Standard Gauge for Sheet Steel — American Iron and Steel Institute