Time, Date, Navigation & Astronomy Celestial Mechanics & Orbits Schwarzschild solution (1916) with CODATA 2018 constants

Schwarzschild Radius Calculator

Enter a mass and this calculator returns the radius at which that mass would become a non-rotating black hole — its Schwarzschild radius, rs = 2GM/c2. Switch the solve mode and it runs the other way, recovering the mass implied by a measured event-horizon size. It also reports the horizon area, the mean density inside the horizon, the Hawking temperature and the evaporation lifetime, so you can see immediately why stellar-mass holes are colder than the cosmic microwave background and why a supermassive hole is less dense than water.

Calculator

This calculator runs in your browser. Enable JavaScript for live results — the inputs, formula and worked example below remain fully readable without it.

Inputs this calculator takes, with typical values
InputWhat to enterExample
Solve forPick which quantity you know; the other one becomes the answer.Radius from mass
MassThe total mass-energy inside the horizon; one solar mass is 1.98841×10³⁰ kg.1 M☉
Event-horizon radiusThe horizon radius you measured or assumed, not its diameter.2.95325 km

It returns

  • Schwarzschild radius — The horizon radius. Double it for the horizon diameter.
  • Schwarzschild radius in kilometres
  • Mass
  • Mass in solar masses
  • Horizon area
  • Mean density inside the horizon
  • Hawking temperature
  • Evaporation lifetime — Time to radiate away completely if nothing falls in and nothing is absorbed.

The formula

rs=2GMc2
A=4πrs2
TH=c38πGMkB
ρ=3c632πG3M2

In plain text: rₛ = 2GM / c²

  • rₛSchwarzschild radius — the event-horizon radius of a non-rotating, uncharged black hole (m)
  • GNewtonian constant of gravitation, 6.67430×10⁻¹¹ (m³ kg⁻¹ s⁻²)
  • MTotal mass inside the horizon (kg)
  • cSpeed of light in vacuum, 299792458 exactly (m/s)

The Schwarzschild solution describes spacetime outside a spherically symmetric, non-rotating, uncharged mass. Real astrophysical holes spin, which shrinks the horizon by up to a factor of two at maximal spin.

Updated Category Celestial Mechanics & Orbits Verified against published test cases Reading time 12 min

What the Schwarzschild radius actually is

The Schwarzschild radius is the radius at which the escape velocity from a mass reaches the speed of light. Compress any object inside that radius and no signal from the interior can reach the outside: the surface at rs becomes an event horizon and the object is a black hole.

Karl Schwarzschild derived it in 1916, within weeks of Einstein publishing the field equations, as the exact vacuum solution outside a spherically symmetric non-rotating mass. The remarkable feature of the result is how little it needs: the horizon radius depends on the mass and on nothing else. Not on composition, not on temperature, not on how the mass got there. Two black holes of the same mass are identical objects.

It is worth being clear about what the number does not mean. The Schwarzschild radius of the Sun is 2.95 km, but the Sun is not a black hole and has no horizon — it is a 696,000 km ball of plasma, and the Schwarzschild solution applies only outside the matter. The 2.95 km figure tells you how small you would have to squeeze the Sun before a horizon formed. For an object that genuinely is a black hole, the same number is the physical size of the horizon.

The horizon is also not a surface in the ordinary sense. Nothing special happens locally as you cross it; an infalling observer in free fall notices no wall. What changes is causal structure: inside, every future-directed path leads to smaller r. That is why the horizon is defined by a radius rather than by a material boundary.

Why the formula is 2GM/c²

The full derivation comes from the Schwarzschild metric, where the coefficient of the time component vanishes at r = 2GM/c2. But a Newtonian argument reaches the same expression and shows where each factor comes from. Set the escape speed equal to c: ½mv² = GMm/r gives v = √(2GM/r), and putting v = c and solving for r returns r = 2GM/c². The agreement is a coincidence of the algebra rather than a justification — the Newtonian argument uses concepts that general relativity discards — but it makes the structure legible.

Mass enters linearly. Double the mass, double the horizon. That single fact drives most of the counter-intuitive behaviour further down this page: area goes as M2, volume as M3, and mean density therefore as M−2.

c2 in the denominator is why horizons are small. With c2 = 8.988×1016 m2/s2, the whole constant 2G/c2 works out to 1.4852×10−27 metres per kilogram. Every kilogram contributes about 1.5 quintillionths of a nanometre.

In practice you rarely want to multiply by 10−27. The useful working constant is the solar-mass scaling: rₛ = 2.95325 km × (M / M☉). A 10-solar-mass stellar remnant has a 29.5 km horizon; a 4.3-million-solar-mass hole like Sagittarius A* has a 1.27×107 km horizon, roughly 17 times the radius of the Sun.

Two companion formulas complete the picture. The horizon area A = 4πrₛ² is the quantity that Hawking proved can never decrease in classical processes, and that Bekenstein tied to entropy. The Hawking temperature T = ℏc³/(8πGMkₖ) is inversely proportional to mass, which is the origin of the strange thermodynamics: a black hole gets hotter as it loses energy.

Worked example: a 10-solar-mass black hole

Take a stellar-mass black hole of 10 M, a typical remnant of a massive star and close to the masses LIGO detects in mergers.

  1. Convert to kilograms. M = 10 × 1.98841×1030 = 1.98841×1031 kg.
  2. Apply the constant. 2G/c2 = 2 × 6.67430×10−11 ÷ 8.98755×1016 = 1.48523×10−27 m/kg.
  3. Multiply. rs = 1.48523×10−27 × 1.98841×1031 = 2.95325×104 m, or 29.53 km. The horizon is 59.07 km across — smaller than most metropolitan areas.
  4. Horizon area. A = 4π(29532.5)2 = 1.0960×1010 m2, about 10,960 km2.
  5. Mean density. Volume = (4/3)π(29532.5)3 = 1.0789×1014 m3, so ρ = 1.98841×1031 ÷ 1.0789×1014 = 1.843×1017 kg/m3, comparable to the density of an atomic nucleus (about 2.3×1017 kg/m3) — if anything, slightly less dense.
  6. Hawking temperature. Scale from the solar value: T = 6.1703×10−8 K ÷ 10 = 6.17×10−9 K. That is nine orders of magnitude colder than the 2.725 K microwave background, so in the real universe this hole absorbs far more than it emits.
  7. Evaporation lifetime. t = 5120πG2M3/(ℏc4) = 2.10×1070 years in an otherwise empty universe.

Check the chain: 1.48523×10−27 × 1.98841×1031 = 2.9533×104, and 4π × (2.95325×104)2 = 4π × 8.7217×108 = 1.0960×1010. Each step reproduces the line below it.

How to read the results

The radius is the only figure that scales gently. Across the 40 orders of magnitude from a kilogram to M87*, the horizon radius tracks mass exactly proportionally, so a mass ratio you can state in words gives a radius ratio you can state in the same words.

Mean density is the figure that surprises people. Because ρ = 3c6/(32πG3M2), doubling the mass quarters the mean density. A solar-mass hole averages 1.8×1019 kg/m3; M87*, at 6.5 billion solar masses, averages 0.44 kg/m3 — about a third the density of air at sea level. This is not a statement about anything you could touch, because the mass is not spread through the horizon volume; it is the ratio of two numbers that happen to scale differently.

The temperature tells you which way energy flows. The Hawking temperature crosses the 2.725 K cosmic microwave background at about 4.5×1022 kg, roughly two thirds of the mass of the Moon. Above that mass a hole is colder than the background, absorbs more than it radiates, and grows. Below it, the hole is hotter than the background and shrinks. The calculator flags which side of that line your input falls on.

Evaporation lifetimes are theoretical. The M3 scaling means a 1011 kg hole — about the mass of a mountain, with a horizon smaller than a proton — would evaporate in roughly the current age of the universe, which is why that mass is the interesting one in primordial black hole searches. Anything of stellar mass survives past 1067 years, long after the background has cooled below its temperature.

Spin is the biggest omission. Real holes rotate. For a maximally spinning Kerr black hole the outer horizon sits at GM/c2, exactly half the Schwarzschild value, so treat the number here as the non-rotating upper bound. Measured spins for stellar-mass holes span nearly the full allowed range, so the correction is not small.

Schwarzschild radius across the mass scale

Every value is 2GM/c2, 4πrs2 and ℏc3/(8πGMkB) evaluated at the stated mass.
ObjectMass (kg)Schwarzschild radiusMean density (kg/m3)Hawking temperature (K)
1 kg1.000×1001.485×10−27 m7.29×10791.227×1023
The Moon7.342×10220.1090 mm1.35×10341.671
Earth5.972×10248.870 mm2.04×10302.054×10−2
Jupiter1.898×10272.819 m2.02×10256.464×10−5
The Sun1.988×10302.953 km1.84×10196.170×10−8
Stellar remnant, 10 M1.988×103129.53 km1.84×10176.170×10−9
Sagittarius A*, 4.3×106 M8.550×10361.270×107 km9.97×1051.435×10−14
M87*, 6.5×109 M1.292×10401.920×1010 km0.4369.493×10−18

Masses for Sagittarius A* and M87* are the Event Horizon Telescope figures. Mean density is M divided by the Euclidean volume of a sphere of radius rₛ, a conventional bookkeeping quantity rather than a physical density.

Which constants this page uses

G = 6.67430×10−11 m3 kg−1 s−2 and ℏ = 1.054571817×10−34 J·s are the CODATA 2018 recommended values; c = 299,792,458 m/s and kB = 1.380649×10−23 J/K are exact by SI definition. The solar mass is taken as 1.98841×1030 kg, which is the IAU 2015 nominal GM = 1.32712440018×1020 m3/s2 divided by G. Astronomers quote GM rather than M because GM is measured to nine significant figures while G alone is known to only about five — which is why rs for the Sun is far better determined than the solar mass itself.

Mistakes and limits worth knowing

  • Confusing radius with diameter. Published "size of the black hole" figures are sometimes diameters. This calculator returns the radius; double it before comparing.
  • Assuming the horizon is what a telescope sees. The bright ring in Event Horizon Telescope images is the photon ring at about 2.6 rs for a non-spinning hole, not the horizon itself. The dark central region is roughly 2.6 times larger in radius than rs.
  • Ignoring spin. The Kerr outer horizon shrinks from 2GM/c2 toward GM/c2 as spin rises to the maximum. Use the Schwarzschild figure as the non-rotating case.
  • Treating mean density as a physical density. It is mass divided by the flat-space volume of a sphere of radius rs. Spacetime inside the horizon is not flat and that volume is not a proper volume.
  • Quoting evaporation lifetimes as forecasts. The lifetime formula assumes an isolated hole radiating into empty space. For anything above about 4.5×1022 kg the microwave background is warmer than the hole today, so the hole grows instead.
  • Applying it to ordinary stars. The Schwarzschild solution holds in vacuum, outside the mass. For the Sun the exterior solution applies only above 696,000 km, and there is no horizon anywhere.

Where this sits among related calculations

The Schwarzschild radius is the entry point to a family of horizon-scale quantities. The photon sphere at 1.5 rs is the radius where light orbits in a circle; the innermost stable circular orbit at 3 rs marks where an accretion disc must end, which sets the efficiency of accretion power. The shadow that a distant observer sees has an apparent radius of √27 GM/c2 ≈ 2.6 rs. All three are fixed multiples of the number this page computes.

For ordinary orbital work outside the horizon you want Kepler's third law, which relates orbital period to semi-major axis and total mass, or the geostationary orbit altitude calculator for the same relation applied to a synchronous orbit. Surface gravity for a body you can stand on is a different formula entirely — see the planetary surface gravity calculator. If you are converting the enormous distances involved into travel times, the light travel time calculator handles light years, parsecs and astronomical units in one place, and the angular size calculator converts a physical horizon size at a known distance into the microarcseconds an interferometer has to resolve.

Historically, the idea predates relativity. John Michell in 1783 and Pierre-Simon Laplace in 1796 both noted that a sufficiently massive, sufficiently compact body would have an escape velocity above the speed of light and would appear dark. Their Newtonian argument gives the same 2GM/c2, but for the wrong reasons and with a completely different physical picture: light was imagined to slow, rise and fall back, rather than to be trapped by causal structure.

Frequently asked questions

What is the Schwarzschild radius of the Sun?

2953.25 metres, or 2.95 km. It follows directly from the IAU nominal solar gravitational parameter: rs = 2 × 1.32712440018×1020 ÷ 8.98755×1016 = 2953.250 m. The Sun is not a black hole; this is the radius it would have to be compressed to before a horizon formed, against an actual radius of about 696,000 km.

What is the Schwarzschild radius of the Earth?

About 8.87 millimetres — roughly the size of a marble. Using GM = 3.986004418×1014 m3/s2, rs = 2 × 3.986004418×1014 ÷ 8.98755×1016 = 0.008870 m. Every kilogram of mass contributes 1.4852×10−27 metres of horizon, so it takes a planet to reach even a centimetre.

Does a black hole's mass have to be huge?

No. Any mass has a Schwarzschild radius; the difficulty is compressing it that far. A 1 kg hole would have a horizon of 1.49×10−27 m, far below the Planck length scale where the formula stops being trustworthy. The smallest holes that could plausibly exist are primordial ones formed in the early universe, and the interesting mass is around 1011–1012 kg because that is the range whose evaporation lifetime is comparable to the age of the universe.

Why is a supermassive black hole less dense than water?

Because the horizon radius grows in proportion to mass while volume grows as the cube of the radius, so mean density falls as 1/M2. M87* at 6.5×109 M has a mean density of 0.44 kg/m3. That figure is mass divided by the flat-space volume of a sphere of radius rs; it is a useful scaling statement, not a description of anything you could put on a scale.

Is the Hawking temperature something that has been measured?

No. For a solar-mass hole it is 6.17×10−8 K, about 44 million times colder than the 2.725 K cosmic microwave background, which makes it undetectable against the background by any known method. Hawking radiation remains a theoretical prediction from quantum field theory in curved spacetime, supported by laboratory analogues rather than by astronomical observation.

How does spin change the answer?

Rotation shrinks the horizon. For a Kerr black hole the outer horizon sits at r+ = (GM/c2)(1 + √(1 − a*2)), where a* is the dimensionless spin between 0 and 1. At a* = 0 this reduces to the Schwarzschild value 2GM/c2; at maximal spin it falls to half of it. Treat the result on this page as the non-rotating limit.

Can I work backwards from an observed horizon size to a mass?

Yes — switch the solve mode to "Mass from radius" and the calculator inverts to M = rsc2/(2G). Be careful about what your measurement actually is: interferometric images resolve the shadow, whose radius is about 2.6 rs for a non-spinning hole, so dividing the observed shadow radius by 2.6 before entering it gives a much better estimate than entering it directly.

What does the evaporation lifetime assume?

An isolated, non-rotating, uncharged hole radiating into empty space with nothing falling in, using t = 5120πG2M3/(ℏc4). The cubic dependence is extreme: halving the mass cuts the lifetime by a factor of eight. Because today's microwave background is warmer than any hole above roughly 4.5×1022 kg, those holes currently gain mass rather than lose it, and their real lifetimes depend on the future cooling of the universe.

References