RLC Series Impedance Calculator

Enter the resistance, inductance and capacitance of a series branch and the frequency it runs at, and this calculator returns the impedance magnitude, the phase angle between voltage and current, the power factor, and the current a given source voltage produces. It shows the inductive and capacitive reactances separately so you can see which one dominates, sweeps the impedance across frequency, and flags where series resonance sits. Leave the inductance or the capacitance at zero to analyse a plain RL or RC branch.

Calculator

This calculator runs in your browser. Enable JavaScript for live results — the inputs, formula and worked example below remain fully readable without it.

Inputs this calculator takes, with typical values
InputWhat to enterExample
Resistance (R)Total series resistance of the branch, including winding and wiring resistance.10 Ω
FrequencyThe supply or signal frequency. Use 60 Hz for North American mains and 50 Hz for most of the rest of the world.60 Hz
Inductance (L)Series inductance. Enter 0 if the branch has no inductor.50 mH
Capacitance (C)Series capacitance. Enter 0 if the branch has no capacitor.100 µF
Source voltage (RMS)The RMS voltage applied across the whole branch; used for the current and power results.120 V

It returns

  • Impedance magnitude — |Z| = √(R² + (XL − XC)²).
  • Phase angle — Positive means current lags voltage; negative means it leads.
  • Power factor
  • Current
  • Inductive reactance XL
  • Capacitive reactance XC
  • Real power
  • Apparent power

The formula

|Z|=R2+(XLXC)2
PF=cosφ=R|Z|
XL=2πfL,XC=12πfC

In plain text: |Z| = √(R² + (X_L − X_C)²), φ = arctan((X_L − X_C)/R)

  • |Z|Impedance magnitude (Ω)
  • RSeries resistance (Ω)
  • X_LInductive reactance, 2πfL (Ω)
  • X_CCapacitive reactance, 1/(2πfC) (Ω)
  • φPhase angle of voltage relative to current (degrees)

Valid for steady-state sinusoidal excitation at a single frequency. Reactances subtract because inductive and capacitive voltages are 180° apart from one another and 90° from the resistive voltage.

Updated Category AC Circuits, Reactance & Resonance Verified against published test cases Reading time 12 min

What impedance is and why it is not just resistance

Impedance is the AC generalisation of resistance: the ratio of voltage to current in a circuit driven by a sinusoid. What makes it different from resistance is that voltage and current need not peak at the same instant. A resistor's voltage and current are exactly in step. An inductor's voltage leads its current by 90°, because voltage across an inductor depends on the rate of change of current. A capacitor's voltage lags its current by 90°, for the mirror-image reason. Impedance carries both the size of the ratio and the timing offset.

That timing is why the three contributions do not simply add. The resistive voltage and the reactive voltage are a quarter-cycle apart, so they combine like the two legs of a right triangle: the total is √(R² + X²), not R + X. The inductive and capacitive voltages, being a half-cycle apart from one another, do subtract directly, which is why the net reactance is X_L − X_C rather than a sum. A 10 Ω resistor in series with 10 Ω of inductive reactance gives 14.14 Ω, not 20 Ω; put 10 Ω of capacitive reactance in with them and you are back to 10 Ω.

The angle matters as much as the magnitude. Its cosine is the power factor, the fraction of the volt-amperes the source supplies that turn into real work. A branch with 0.6 power factor draws 67% more current than a resistive load doing the same job, and that extra current heats conductors, loads transformers and, on a commercial tariff, costs money. Reactive elements return their energy to the source each half-cycle rather than consuming it, so they contribute nothing to the watts but everything to the amps.

All of this assumes one steady sinusoidal frequency. If the excitation contains harmonics, work each frequency separately — the reactances differ at each one — and combine the results. For the individual reactance terms alone, the inductive reactance calculator and capacitive reactance calculator are quicker.

Reading the formula as a triangle

Draw the impedance triangle and every result on this page becomes obvious. Put R along the horizontal axis. Put the net reactance X = X_L − X_C along the vertical axis, upward when inductive reactance wins and downward when capacitive wins. The hypotenuse is |Z| and the angle it makes with the horizontal is φ. Then:

  • |Z| = √(R² + X²) is Pythagoras.
  • φ = arctan(X/R) is the angle of that hypotenuse, positive for a net inductive branch and negative for a net capacitive one.
  • PF = cos φ = R/|Z| is the adjacent side over the hypotenuse.

The same triangle scales into the power triangle. Multiply every side by the current squared and the horizontal leg becomes real power in watts, the vertical leg becomes reactive power in VAR and the hypotenuse becomes apparent power in volt-amperes. That is why power factor and phase angle carry the same information.

Both reactances depend on frequency, and in opposite directions. X_L = 2πfL rises without limit as frequency rises; X_C = 1/(2πfC) falls towards zero. Somewhere they are equal, and at that frequency the vertical leg of the triangle vanishes: the branch looks purely resistive, the impedance falls to R alone and the current peaks. That is series resonance, at f₀ = 1/(2π√(LC)), and the resonant frequency calculator covers the Q and bandwidth that go with it.

Sign conventions cause more confusion than the algebra. A positive phase angle here means the voltage leads the current, which is the same as saying the current lags — the normal state for motors and transformers. A negative angle means the current leads, which is what a capacitor-dominated branch does. Power factor itself is always reported as a positive number between 0 and 1, with the words “lagging” or “leading” carrying the sign.

Worked example: 10 Ω, 50 mH and 100 µF on 120 V at 60 Hz

A series branch of 10 Ω, 50 mH and 100 µF is connected across 120 V, 60 Hz. Find the impedance, the phase and the current.

  1. Angular frequency. ω = 2πf = 6.283185 × 60 = 376.9911 rad/s.
  2. Inductive reactance. X_L = ωL = 376.9911 × 0.050 = 18.8496 Ω.
  3. Capacitive reactance. X_C = 1/(ωC) = 1/(376.9911 × 1.0000 × 10⁻⁴) = 1/0.0376991 = 26.5258 Ω.
  4. Net reactance. X = 18.8496 − 26.5258 = −7.6763 Ω. Negative, so this branch is capacitive at 60 Hz.
  5. Impedance. |Z| = √(10² + (−7.6763)²) = √(100 + 58.9251) = √158.9251 = 12.6066 Ω.
  6. Phase. φ = arctan(−7.6763 / 10) = arctan(−0.76763) = −37.511°. The current leads the voltage.
  7. Power factor. PF = R/|Z| = 10 / 12.6066 = 0.7932, leading.
  8. Current. I = V/|Z| = 120 / 12.6066 = 9.5189 A.
  9. Power. P = I²R = 9.5189² × 10 = 90.609 × 10 = 906.1 W. Apparent power S = V × I = 120 × 9.5189 = 1,142.3 VA. Check: P/S = 906.1/1,142.3 = 0.7932, the power factor again.

Where does resonance sit for these parts? f₀ = 1/(2π√(0.050 × 1.0000 × 10⁻⁴)) = 1/(2π√(5.0000 × 10⁻⁶)) = 1/(6.283185 × 2.23607 × 10⁻³) = 1/0.0140496 = 71.176 Hz. That is above 60 Hz, which confirms the sign we found: below resonance the capacitive term is the larger one. Drive the same branch at 71.176 Hz and the impedance drops to 10.000 Ω and the current rises to 12.000 A, its maximum.

How to read the phase angle and power factor

Start with the sign of the phase angle, because it tells you what kind of load you have. A positive angle — current lagging — is the signature of motors, transformers, ballasts and solenoids, anything built around a winding. A negative angle — current leading — comes from capacitance: long lightly loaded cables, over-sized correction capacitor banks, and some switch-mode front ends. Both cost you the same in extra current, and utilities penalise both.

Then read the power factor against the standard. Most industrial tariffs set a threshold around 0.90 to 0.95 lagging and bill demand on kVA or apply a penalty below the threshold; the exact figure is set by your utility's tariff document, so read yours rather than assuming a number. A power factor of 0.79 means the source supplies 1/0.79 = 1.27 times the current a unity-power-factor load would need for the same watts, and conductor heating goes as current squared, so 1.27² = 1.60 times the I²R loss in the feeder. That is the real cost of a poor power factor even where there is no tariff penalty. Correcting it is what the power factor correction calculator sizes.

Compare the two reactances directly. Whichever is larger sets the character of the branch, and the difference between them is what actually appears in the impedance. Two components of 100 Ω and 90 Ω reactance contribute only 10 Ω of net reactance, and the individual voltage across each of them is still large — which is the trap in series-resonant circuits, where the voltage across L and across C can each far exceed the supply while the branch as a whole looks benign.

Finally, check the current against the components' ratings, not just against the source. A 9.52 A current through a 100 µF capacitor puts 9.52 × 26.53 = 252.5 V across it — more than the 120 V supply. Capacitor voltage ratings and inductor current ratings are separate constraints that the impedance magnitude alone does not reveal.

Reactance at common frequencies

X_L = 2πfL and X_C = 1/(2πfC) evaluated at the frequencies most series branches run at. Inductive reactance is proportional to frequency; capacitive reactance is inversely proportional.
Component50 Hz60 Hz400 Hz1 kHz
1 mH inductor0.3142 Ω0.3770 Ω2.513 Ω6.283 Ω
50 mH inductor15.708 Ω18.850 Ω125.66 Ω314.16 Ω
1 H inductor314.16 Ω376.99 Ω2,513.3 Ω6,283.2 Ω
1 µF capacitor3,183.1 Ω2,652.6 Ω397.89 Ω159.15 Ω
10 µF capacitor318.31 Ω265.26 Ω39.789 Ω15.915 Ω
100 µF capacitor31.831 Ω26.526 Ω3.9789 Ω1.5915 Ω

Every inductive row scales linearly with frequency and every capacitive row scales inversely, so you can read any other value off by proportion — a 25 mH coil is half the 50 mH row, and 400 Hz aircraft power gives an inductor about 6.67 times the reactance it has at 60 Hz.

Assumptions and common errors

  • Adding R and X arithmetically. They are 90° apart, so 10 Ω of resistance with 10 Ω of reactance gives 14.14 Ω, not 20 Ω. Only X_L and X_C subtract directly, because they are 180° apart from each other.
  • Treating an inductor as pure inductance. Real coils have winding resistance and, at higher frequencies, core loss and self-capacitance. Measure the branch resistance rather than assuming it is negligible; it is what sets the power factor and the current at resonance.
  • Using this on a distorted waveform. The whole method assumes one sinusoid. With harmonics present, each order sees a different reactance, and the true power factor includes a distortion term that no impedance triangle captures.
  • Ignoring the voltage across individual reactive elements. Near series resonance those voltages are magnified by the circuit Q and can be many times the supply, which is invisible if you only look at |Z|.
  • Mixing peak and RMS values. The impedance is the same either way, but the current and power results only mean what you expect when the voltage you entered is RMS.
  • Applying the series formula to a parallel circuit. Parallel branches combine by admittance, not by adding impedances, and a parallel tank behaves in the opposite way at resonance — maximum impedance rather than minimum.

Key terms

Reactance (X)
The opposition to alternating current from energy storage rather than dissipation, in ohms. Inductive reactance is positive and rises with frequency; capacitive reactance is negative and falls with frequency.
Impedance (Z)
The complex ratio of voltage to current, combining resistance and reactance. Its magnitude sets the current and its angle sets the phase relationship.
Power factor
The cosine of the phase angle, equal to real power divided by apparent power. Described as lagging when the current lags the voltage and leading when it leads.
Series resonance
The frequency at which inductive and capacitive reactances are equal, so they cancel and the branch impedance falls to its resistance alone.

Where this fits in AC analysis

The series RLC branch is the smallest circuit that contains everything AC analysis has to handle: dissipation, two kinds of energy storage, a frequency-dependent response and a phase relationship. Every larger analysis is built from it. Motor equivalent circuits are an RL series branch with a second branch for the magnetising current; transmission line models are series RL with shunt capacitance; a loudspeaker's electrical impedance is a series RLC around its mechanical resonance.

In power work the numbers here feed directly into two decisions. First, conductor sizing: it is the current, not the power, that heats a conductor, and a poor power factor raises the current for the same watts — the wire size and ampacity calculator takes that current and returns the conductor. Second, correction: knowing the reactive power lets you size the capacitor bank that cancels it. For three-phase systems the same triangle applies per phase, with the √3 factors that the three-phase power calculator handles.

In electronics the same arithmetic describes filters and matching networks. A series RC branch is a first-order high-pass or low-pass depending on where you take the output, which is what the RC filter calculator works out in decibels rather than ohms. Adding the inductor makes the response second-order and introduces the resonant peak.

When you need more than a single-frequency answer — a full frequency response, a transient, or a network with several loops — the tools are circuit simulation and Laplace-domain analysis. The impedance you compute here is exactly what a simulator evaluates at each frequency point, so the two agree by construction, and hand-checking one frequency against a simulation is the fastest way to catch a wrong component value.

Frequently asked questions

Why do the reactances subtract instead of adding?

Because inductive and capacitive voltages are 180° apart from each other. An inductor's voltage leads its current by 90° and a capacitor's lags by 90°, so in a series branch carrying one common current those two voltages are in direct opposition and cancel. The resistive voltage is 90° from both, which is why it combines with the net reactance through Pythagoras rather than by subtraction.

What does a negative phase angle mean?

It means the current leads the voltage, so the branch is net capacitive: X_C is larger than X_L at the frequency you entered. A positive angle means the current lags and the branch is net inductive, which is the usual case for motors and transformers. Either way the power factor is reported as a positive number, with the sign of the angle telling you whether it is leading or lagging.

How do I analyse an RL circuit with no capacitor?

Enter 0 for the capacitance. The calculator then treats X_C as zero, so the net reactance is just X_L and the impedance is √(R² + X_L²) with a positive phase angle. Do the same with the inductance for a plain RC branch. With both at zero the branch is resistive, the phase angle is zero and the power factor is 1.

Is impedance the same as AC resistance?

No. Impedance includes both the dissipative part, resistance, and the storage part, reactance, and it carries a phase angle. Only the resistive part converts electrical energy into heat or work; the reactive part exchanges energy with the source twice per cycle and consumes nothing on average. Two branches with the same impedance magnitude can dissipate very different amounts of power.

What power factor should I be aiming for?

Check your utility tariff rather than a rule of thumb, because the threshold and the penalty structure vary by supplier and by region. What is universally true is the physics: at power factor PF the current for a given real power is 1/PF times the unity-power-factor current, and conductor loss scales with the square of that. Correcting from 0.80 to 0.95 cuts the current by 16% and the feeder loss by about 29%.

Why is the voltage across my capacitor higher than the supply voltage?

Because near series resonance the reactive voltages are magnified. The current through the branch is set by the small net impedance, but that same current flows through the full reactance of each individual element, so V_C = I × X_C can be several times the applied voltage. The inductor's voltage is equally large and opposite, which is why the two cancel from the source's point of view.

Does this work at 400 Hz or at radio frequencies?

The formulas hold at any frequency, and the calculator accepts up to 10 GHz. What stops being true is the lumped-element model: above a few tens of megahertz, capacitor lead inductance, coil self-capacitance and the physical size of the components relative to a wavelength all matter, and the parts stop behaving as ideal L and C. Measure at frequency rather than trusting a datasheet value taken at 1 kHz.

How do I handle a parallel RLC instead of a series one?

Work in admittances. Compute each branch's admittance as the reciprocal of its impedance, add them as complex numbers, then invert the total. The behaviour at resonance is the opposite of the series case: impedance is maximum, line current is minimum, and a large current circulates between the inductor and the capacitor.

References

  • Fundamentals of Electric Circuits, 6th ed. — McGraw-Hill Education (Alexander & Sadiku)
  • Standard Handbook for Electrical Engineers, 17th ed. — McGraw-Hill Education
  • The Art of Electronics, 3rd ed. — Cambridge University Press (Horowitz & Hill)