Professional Licensing & Applied Exam Math Surveying & Highway Geometry AASHTO Green Book geometric design conventions

Horizontal Curve Layout Calculator

Give this calculator a radius or a degree of curve, the deflection angle between the two tangents, and the station of the point of intersection, and it returns every element needed to lay out a simple circular curve: tangent distance T, curve length L, long chord LC, middle ordinate M, external distance E, and the stations of the PC and PT. It also builds the deflection-angle table a party chief needs to stake the curve from the PC with a total station, at whatever full-station interval the alignment uses.

Calculator

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Inputs this calculator takes, with typical values
InputWhat to enterExample
Define the curve byModern plans give a radius; older highway and railroad plans give a degree of curve.Radius R
Radius RCentreline radius from the plan. Ignored when you define the curve by degree of curve.1000 ft
Degree of curve DCentral angle subtended by a 100 ft arc or chord. Ignored when you define the curve by radius.5.729578 °
Degree-of-curve definitionHighway practice measures the 100 ft along the arc; railroad practice measures it along the chord.Arc definition (highways)
Deflection (intersection) angle ΔAngle between the back and forward tangents, equal to the central angle of the curve.30 °
PI stationStation of the point of intersection along the alignment, entered as a plain distance (100+00 is 10000).10000 ft
Staking intervalSpacing of the deflection-angle table; tighten it on sharp curves so chords hug the arc.100 ft (full station)

It returns

  • Tangent distance T — Distance back from the PI to the PC, and forward from the PI to the PT.
  • Curve length L (arc)
  • Long chord LC
  • Middle ordinate M
  • External distance E
  • Radius R
  • PC station
  • PT station

The formula

T=Rtan(Δ2),L=πRΔ180
R=5729.578D,R=50sin(D/2)
δ=lLΔ2

In plain text: T = R·tan(Δ/2) L = R·Δ·π/180 LC = 2R·sin(Δ/2) M = R(1 − cos(Δ/2)) E = R(sec(Δ/2) − 1)

  • RRadius of the circular curve (ft)
  • ΔDeflection angle between the tangents, equal to the central angle (°)
  • TTangent distance from PI to PC and from PI to PT (ft)
  • LLength of the curve measured along the arc (ft)
  • LCLong chord, straight line from PC to PT (ft)
  • MMiddle ordinate, from midpoint of the long chord to the curve (ft)
  • EExternal distance, from the PI to the midpoint of the curve (ft)

All seven elements come from the same isosceles geometry: the tangents are equal, the radii to PC and PT are perpendicular to them, and the central angle equals the deflection angle between the tangents.

Updated Category Surveying & Highway Geometry Verified against published test cases Reading time 12 min

What a simple circular curve is made of

A highway alignment is a sequence of straight tangents. Where two tangents meet, at the point of intersection or PI, a circular arc is inserted so that vehicles can change direction at speed. The arc leaves the back tangent at the PC (point of curvature) and rejoins the forward tangent at the PT (point of tangency), touching each tangent without a kink.

Because the radii to the PC and the PT are perpendicular to their tangents, the central angle of the arc is exactly the angle between the tangents. That single fact gives you everything else. The figure PI–PC–centre–PT is a kite with two right angles, so the two tangent distances are equal, and the whole curve is symmetric about the line from the PI to the centre.

Six numbers describe the curve. T tells you where to set the PC and PT relative to the PI. L is what goes in the stationing, because alignment stations follow the arc, not the tangents. LC is the straight-line distance between the two ends. M is the offset from the middle of that chord to the curve, and it is the number that governs sight distance past an obstruction on the inside of the curve. E is the offset from the PI to the curve, which tells you how far outside the intersection the pavement actually runs.

Where each formula comes from

Drop a line from the PI to the centre of the circle. It bisects the angle Δ, so it forms a right triangle with the radius and one tangent, containing the angle Δ/2 at the centre.

T = R·tan(Δ/2) is the opposite over adjacent in that triangle. Notice that the tangent function grows without limit as Δ approaches 180°, which is why a near-reversal cannot be made with a single curve of any usable radius.

L = R·Δ·π/180 is nothing but arc length. Δ must be converted to radians, which is where the π/180 comes from. If you are working in degree of curve on the arc definition, there is a much easier form: L = 100·Δ/D, because D is defined as the angle subtended by exactly 100 ft of arc.

LC = 2R·sin(Δ/2) is the chord of a central angle Δ, split into two right triangles of half-angle each.

M = R(1 − cos(Δ/2)) is the radius minus its projection onto the bisector. Because the cosine is nearly 1 for small angles, M is tiny on flat curves and grows quickly on sharp ones.

E = R(sec(Δ/2) − 1) is the hypotenuse from the centre to the PI minus the radius. E is always larger than M, and both approach infinity with T as Δ approaches 180°.

The degree of curve is an older way of stating sharpness that survives on highway and railroad plans. Under the arc definition, D is the central angle subtended by a 100 ft arc, so R = 100 × (360/2π) / D = 5729.578/D. Under the chord definition, used by railroads, D subtends a 100 ft chord, giving R = 50/sin(D/2). The two agree to within a foot on flat curves and diverge on sharp ones — 1,432.39 ft against 1,432.69 ft at D = 4°, but 286.48 ft against 287.94 ft at D = 20°.

Worked example: R = 1,000 ft, Δ = 30°, PI at station 100+00

A two-lane road turns 30° to the right. The designer has chosen a 1,000 ft radius and the PI falls at station 100+00, that is 10,000.00 ft along the alignment.

  1. Half the deflection. Δ/2 = 30 ÷ 2 = 15°.
  2. Tangent distance. T = 1,000 × tan 15° = 1,000 × 0.267949 = 267.949 ft.
  3. Curve length. L = 1,000 × 30 × π ÷ 180 = 1,000 × 0.523599 = 523.599 ft.
  4. Long chord. LC = 2 × 1,000 × sin 15° = 2,000 × 0.258819 = 517.638 ft. It is 5.96 ft shorter than the arc, as it must be.
  5. Middle ordinate. M = 1,000 × (1 − cos 15°) = 1,000 × (1 − 0.965926) = 34.074 ft.
  6. External distance. E = 1,000 × (1 ÷ cos 15° − 1) = 1,000 × (1.035276 − 1) = 35.276 ft.
  7. PC station. 10,000.000 − 267.949 = 9,732.051 ft = station 97+32.05.
  8. PT station. 9,732.051 + 523.599 = 10,255.650 ft = station 102+55.65.

The PT is not at the PI station plus T. Going around the curve is 523.599 ft while going out to the PI and back is 2 × 267.949 = 535.898 ft, so the alignment loses 12.30 ft of stationing at this PI. That difference — the tangent deficiency — is the single most common source of station errors on a curved alignment.

Staking check. To stake station 98+00 from the PC, the arc distance is 9,800.00 − 9,732.05 = 67.95 ft, so the deflection angle is (67.95 ÷ 523.599) × 15° = 1.9466°, that is 1°56′48″, and the chord from the PC is 2 × 1,000 × sin 1.9466° = 67.94 ft. The final deflection, at the PT, is always exactly Δ/2 = 15°00′00″, which is the field check that the whole set of angles is right.

Reading the numbers as a designer

Middle ordinate is the sight-distance number. A barrier, cut slope or building on the inside of a curve blocks the driver's line of sight. The relationship M = R(1 − cos(Δ/2)) applied to the sight-distance sub-arc rather than the whole curve gives the horizontal sightline offset, which AASHTO uses to set the clear zone inside a curve. If M for the sight sub-arc exceeds the available offset to the obstruction, the design speed cannot be met.

External distance tells you whether the curve fits. On a constrained corner — an urban intersection, a bridge approach, a corner of a parcel — E is the amount by which the pavement centreline runs outside the PI. Compare it to the available right of way before anything else.

Tangent distance decides whether adjacent curves collide. Two successive PIs must be far enough apart that the PT of the first curve precedes the PC of the second, with tangent between them for superelevation runoff. When the tangent lengths overlap, you need a compound or reverse curve rather than two simple ones, or a larger radius.

Curve length drives the stationing of everything downstream. Every station after the PT shifts by the tangent deficiency 2T − L. Set the PC and PT correctly and the rest of the alignment follows; get them wrong and every culvert, drive and utility crossing beyond the curve is misplaced by the same amount.

Radius has to satisfy the speed, not the other way round. The minimum radius for a design speed comes from R = V² / (15(e + f)) with V in mph, e the superelevation rate and f the side-friction factor. That relationship, not the geometry on this page, is what sets the smallest curve you are allowed to use.

Degree of curve and radius, both definitions

Arc-definition radius is 5729.578/D; chord-definition radius is 50/sin(D/2). Highway plans use the arc definition, railroad plans the chord definition.
Degree of curve DArc-definition R (ft)Chord-definition R (ft)Difference (ft)
5,729.585,729.650.07
2,864.792,864.930.14
1,909.861,910.080.22
1,432.391,432.690.30
1,145.921,146.280.36
954.93955.370.44
716.20716.780.58
10°572.96573.690.73
15°381.97383.071.10
20°286.48287.941.46

The two definitions differ by less than a tenth of a foot below D = 1° and by nearly a foot and a half at D = 20°. Always state which definition a plan uses before converting.

Errors that put a curve in the wrong place

  • Computing the PT as PI + T. Stationing runs along the arc, so PT = PC + L. The difference 2T − L is 12.30 ft on the worked example and grows rapidly with Δ.
  • Mixing the arc and chord definitions. A 20° curve differs by 1.46 ft in radius between the two, which is more than the tolerance on any staking.
  • Forgetting that Δ is the tangent deflection, not the interior angle at the PI. If the field book records the interior angle I, then Δ = 180° − I.
  • Using the long chord where the arc is required. Pavement quantities, guardrail lengths and stationing all follow L; only the straight-line tie between PC and PT is LC.
  • Staking long chords on a sharp curve. The mid-ordinate of a sub-chord grows with the square of its length. On a 200 ft radius, a 100 ft sub-chord departs from the arc by about 3.1 ft at its midpoint, so tighten the interval to 25 ft.
  • Ignoring the spiral. Most modern high-speed alignments insert a spiral transition between tangent and circular arc. The circular portion still uses these formulas, but T, PC and PT all shift, and the spiral has its own set of elements.
  • Treating a right deflection and a left deflection the same in the field. The geometry is identical, but the deflection angles are turned in the opposite rotational sense from the back tangent.

Simple curves among the alternatives

A simple curve — one arc of one radius — is the base case and covers most low-speed and rural work. A compound curve joins two arcs of different radii turning the same way, used where terrain or right of way makes a single radius impossible. A reverse curve joins two arcs turning opposite ways; without a tangent between them, superelevation cannot be run off and drivers get a sudden steering reversal, so agencies restrict them. A spiral (clothoid) has a radius that decreases linearly with length, matching the path a driver actually steers and allowing superelevation to be introduced gradually.

Before any of these can be laid out you need the alignment directions, which arrive as bearings or azimuths from the traverse — the bearing to azimuth converter handles the notation, and the deflection angle Δ is simply the difference between the back-tangent and forward-tangent azimuths. Once the curve is staked, the same alignment drives earthwork quantities through a cut and fill computation, the utility trenches through a trench volume estimate, and the surfacing through an asphalt tonnage estimate once the paved area is known.

Vertical curves are the other half of alignment geometry and use a completely different shape: a parabola, not a circle, because it produces a constant rate of grade change. Do not carry the formulas on this page over to a crest or sag curve.

Key terms

PI — point of intersection
Where the two tangents would meet if extended. The curve does not pass through it; the external distance E measures how far short of it the curve runs.
PC and PT
Point of curvature and point of tangency: where the curve leaves the back tangent and rejoins the forward tangent. Also written BC/EC or TS/ST on spiralled alignments.
Station
Distance along the alignment, written in hundreds of feet: station 102+55.65 is 10,255.65 ft from the alignment origin. Metric alignments station in kilometres with the same plus notation.
Deflection angle (staking)
Half the central angle subtended by an arc, turned from the back tangent at the PC. It is what the instrument reads; the chord is what the tape or EDM measures.
Tangent deficiency
2T − L, the amount of stationing lost by cutting the corner. Every station beyond the PT shifts by this quantity.
Superelevation
The cross-slope banking of the roadway through a curve, expressed as a rate e. Together with the side-friction factor it sets the minimum radius for a design speed.

Frequently asked questions

Why is the PT station not the PI station plus the tangent distance?

Because stationing follows the road, and the road goes around the arc rather than out to the corner and back. The PC is at PI − T, and from there you add the arc length L, not T. On the worked example the two paths differ by 2 × 267.949 − 523.599 = 12.30 ft, so every station beyond the PT is 12.30 ft less than a tangent-only computation would suggest. On sharp curves this tangent deficiency can be hundreds of feet.

Which degree-of-curve definition should I use?

Use whichever the plan states. Highway agencies in the United States use the arc definition, where D is the central angle over 100 ft of arc, giving R = 5729.578/D. Railroads use the chord definition, where the 100 ft is a straight chord, giving R = 50/sin(D/2). At D = 4° they differ by 0.30 ft in radius and at D = 20° by 1.46 ft. If the plan does not say and the project is a road, assume arc.

How do I get the deflection angle Δ from field bearings?

Δ is the difference between the azimuth of the forward tangent and the azimuth of the back tangent, reduced to a value under 180°. If the alignment runs on azimuth 42°15′ and turns to azimuth 72°15′, then Δ = 30°00′ to the right. If your field book records the interior angle I at the PI instead, use Δ = 180° − I.

What staking interval should I use?

Full 100 ft stations are standard on flat curves; drop to 50 ft below about a 500 ft radius and 25 ft below about a 200 ft radius. The rule behind those numbers is that a chord departs from its arc by roughly c²/(8R) at the midpoint, so a 100 ft chord on a 200 ft radius misses the true alignment by about 3.1 ft, while the same chord on a 1,000 ft radius misses by 0.63 ft.

What is the middle ordinate used for besides layout?

Sight distance. Applied to the sight-distance sub-arc rather than the whole curve, M gives the horizontal offset a driver's line of sight cuts across the inside of the curve, which is the number AASHTO uses to set how far back a barrier, cut slope or wall must sit. If the available offset is less than the required middle ordinate, the design speed has to come down or the radius has to go up.

Can this calculator handle a spiral transition?

No — it solves a simple circular curve only. On a spiralled alignment the tangent runs into a spiral at the TS, the spiral meets the circular arc at the SC, and the circular portion is shorter than it would be without the spirals. The circular arc still obeys these formulas, but the tangent distance, external distance and station equations all change and require the spiral parameters (length Ls and the shift p).

What happens as the deflection angle approaches 180 degrees?

The tangent distance and the external distance both grow without bound, because the two tangents become parallel and their intersection recedes to infinity. Practically, a deflection above about 120° is already awkward: at Δ = 120° the tangent distance is 1.73 R and the external distance is R itself, so the PI sits a full radius outside the pavement. Near-reversals are handled with a compound or reverse curve, not one simple arc.

Does this work in metres?

The geometry does, and the radius and PI station inputs accept metres. What does not carry over is the degree of curve, which is defined on a 100 ft arc or chord and has no metric equivalent in general use — metric alignments quote radius directly. Metric stationing also uses 1 km stations rather than 100 ft ones, so read the station notation in the deflection table as a plain distance when you work in metres.

References

  • A Policy on Geometric Design of Highways and Streets (the Green Book), 7th ed. — American Association of State Highway and Transportation Officials (AASHTO)
  • Elementary Surveying: An Introduction to Geomatics, 15th ed. — circular curves — C. D. Ghilani and P. R. Wolf, Pearson
  • Route Surveying and Design, 5th ed. — C. F. Meyer and D. W. Gibson, Harper & Row
  • FS/PS Reference Handbook — horizontal curve elements — National Council of Examiners for Engineering and Surveying (NCEES)