Music Theory, Audio Engineering & Instruments Studio & Live Audio Engineering Energy summation of levels; geometric spreading per ISO 9613-2

Decibel Addition Calculator (Combining Sound Sources)

Decibels are logarithms, so they do not add. Two machines at 85 dB each do not make 170 dB, and they do not make 85 dB either - they make 88.01 dB, because the underlying energies add and the logarithm of twice as much energy is 3.01 dB more. This calculator combines any set of levels correctly, shows what share of the total each source contributes, tells you what removing any one of them would achieve, and applies a distance correction for a point or line source.

Calculator

This calculator runs in your browser. Enable JavaScript for live results — the inputs, formula and worked example below remain fully readable without it.

Inputs this calculator takes, with typical values
InputWhat to enterExample
SourcesUse individual levels for a real survey; use identical sources to see what adding more of the same does.Individual levels
How many sourcesOnly this many of the level fields below are used.3
Source 1 levelSound pressure level of the first source at the measuring position.85 dB
Source 2 levelSecond source, measured the same way and at the same position as the first.82 dB
Source 3 levelThird source. Levels more than 10 dB below the loudest add very little.78 dB
Source 4 levelFourth source, if there is one.75 dB
Level of each sourceThe level one source produces on its own at the measuring position.85 dB
Number of identical sourcesAdding n identical sources raises the level by 10 x log10(n).4
Distance the levels were measured atThe reference distance for the levels you entered. One metre is the usual specification distance.1 m
Distance you want the level atWhere the listener or the measurement point is. Leave equal to the reference for no correction.10 m
Source geometryA single loudspeaker or machine behaves as a point source; a long line array or a stream of traffic behaves as a line.Point source - 6 dB per doubling

It returns

  • Combined level at the reference distance — The energy sum of every source you entered.
  • Increase over the loudest source alone
  • Loudest single source
  • Share of the total from the loudest source
  • Level if you doubled everything
  • Combined level at the target distance

The formula

Ltotal=10log10(i=1n10Li10)
Ltotal=L+10log10(n)
ΔL=20log10(r2r1)

In plain text: L_total = 10 x log10( sum of 10^(L_i / 10) )

  • L_totalCombined sound pressure level (dB)
  • L_iLevel of source i at the same measuring position (dB)
  • nNumber of sources (integer)

The exponent is divided by 10 rather than 20 because the decibel for a power-like quantity uses 10 log, and mean-square sound pressure is power-like. Levels are converted back to relative energy, summed, and converted again.

Updated Category Studio & Live Audio Engineering Verified against published test cases Reading time 11 min

Why decibels cannot be added directly

A decibel is not a quantity of sound; it is a logarithm of a ratio. A sound pressure level of 85 dB means the mean-square pressure is 108.5 times the reference of 20 micropascals squared. Logarithms turn multiplication into addition, which is exactly why they are convenient - and exactly why adding the logarithms of two sources gives you the logarithm of their product, which is meaningless here.

What actually adds is energy. Two independent sources deliver twice the acoustic energy of one, and the level corresponding to twice the energy is 10 x log10(2) = 3.0103 dB more. That single number governs the whole subject: every doubling of the number of identical sources adds 3.01 dB, and no amount of doubling ever adds more. Ten sources add 10 dB, a hundred add 20 dB, a thousand add 30 dB.

The consequence that surprises people is how little a quieter source matters. A source 10 dB below the loudest contributes 10 x log10(1 + 0.1) = 0.41 dB. A source 20 dB below contributes 0.04 dB, which is below the resolution of most meters. If you are trying to reduce a noise problem, this is the most useful fact on the page: silencing anything more than about 10 dB below the dominant source is effort spent for nothing.

The formula, and where the 10 and the 20 come from

Convert each level back to a relative energy with 10L/10, add those numbers, and convert the sum back with 10 x log10. That is the whole calculation. Nothing about it depends on the sources being of the same type, and it applies equally to sound power levels, sound pressure levels and electrical power levels - anything defined with a 10 log convention.

The choice between 10 log and 20 log is a persistent source of confusion, and it is not arbitrary. Power-like quantities - power, intensity, mean-square pressure, energy - use 10 log. Amplitude-like quantities - voltage, sound pressure itself, current - use 20 log, because power goes as amplitude squared and log(x2) = 2 log(x). A sound pressure level is already defined through the squared pressure, so it is power-like and combines with 10 log. This is why doubling the number of sources gives 3.01 dB while doubling the voltage into a resistor gives 6.02 dB.

Distance follows from the same reasoning. A point source radiating into free space spreads its power over a sphere whose area grows as the square of the radius, so intensity falls as 1/r2 and the level falls by 20 x log10(r2/r1) - which is 6.02 dB per doubling of distance. An idealised infinite line source spreads over a cylinder whose area grows only linearly with radius, so the fall is 10 x log10(r2/r1), or 3.01 dB per doubling. ISO 9613-2 treats geometric spreading this way and then adds terms for air absorption, ground effect and screening, all of which this calculator excludes.

One important assumption underlies all of it: the sources must be uncorrelated. Independent machines, separate instruments and a band on stage all qualify. Two loudspeakers fed the same signal do not - they are coherent, and coherent sources add in pressure rather than in energy, giving up to 6.02 dB where they arrive in phase and cancelling where they arrive in antiphase. The delay and reverb time calculator covers the timing side of that interference.

Worked example: four machines in a workshop

Four machines are measured individually at the operator's position: 85, 82, 78 and 75 dB. What is the total, and what would silencing each one achieve?

  1. Convert each to relative energy. 108.5 = 316,227,766; 108.2 = 158,489,319; 107.8 = 63,095,734; 107.5 = 31,622,777.
  2. Add them. 316,227,766 + 158,489,319 + 63,095,734 + 31,622,777 = 569,435,596.
  3. Convert back. 10 x log10(569,435,596) = 10 x 8.75536 = 87.55 dB.
  4. Compare with the loudest alone. 87.55 − 85 = 2.55 dB gained from the other three combined.
  5. Shares. The 85 dB machine is 316,227,766 / 569,435,596 = 55.5% of the energy; the 82 dB machine is 27.8%; the 78 dB machine 11.1%; the 75 dB machine 5.6%.
  6. Silence the quietest. The remaining sum is 537,812,819, giving 10 x log10(537,812,819) = 87.31 dB - a saving of just 0.25 dB, which nobody can hear.
  7. Silence the loudest instead. The remaining sum is 253,207,830, giving 84.03 dB - a saving of 3.52 dB, fourteen times as much benefit for the same piece of work.
  8. Take the total out to 10 m. If those levels were measured at 1 m and the machines behave as point sources, the correction is −20 x log10(10/1) = −20 dB, giving 67.55 dB at 10 m.

Step 7 is the point of the whole exercise. Noise control money goes to the dominant source, and the share column tells you which that is far more clearly than the raw levels do.

Reading the increase figure

The increase over the loudest source is the number that tells you whether the other sources matter. If it is under 0.5 dB, the problem is one source and everything else is noise in the accounting. If it is close to 3 dB you have two comparable sources and must deal with both. If it is close to 6 dB you have four comparable sources, and to 10 dB you have ten.

Translating decibels into perception needs care and honest hedging. A 3 dB change is at the edge of noticeable on a steady sound heard alone, though it is easy to hear as an A/B comparison. A 10 dB change is conventionally described as a doubling or halving of loudness, a rule of thumb from loudness scaling experiments rather than a physical fact - and it corresponds to ten times the acoustic energy. That gap between energy and perception is why turning off nine of ten identical machines only halves the perceived loudness.

Two cautions about comparing a computed total against a limit. First, weighting: occupational and environmental criteria are defined on A-weighted levels, which de-emphasise low frequencies to approximate the ear's response at moderate levels. An unweighted total and an A-weighted limit are different quantities and cannot be compared. Second, time: exposure standards are stated as time-weighted averages over a shift, not as instantaneous levels, so a momentary figure from this calculator is not directly a compliance number.

For distance, remember the correction only covers geometric spreading. Outdoors, air absorption removes additional energy that grows with distance and strongly with frequency; ground and barriers change things further. Indoors, the reverberant field dominates beyond the critical distance, and beyond that point moving further away barely reduces the level at all - which is why the inverse square law usually fails badly in a real room.

How much a second source adds

Add this figure to the higher of the two levels. The value is 10 x log10(1 + 10^(-d/10)), where d is the difference between them.
Difference between the two levels (dB)Add to the higher level (dB)Share of the quieter source (%)
03.0150.0
12.5444.3
22.1238.7
31.7633.4
41.4628.5
51.1924.0
60.9720.1
80.6413.7
100.419.1
150.143.1
200.041.0

Read the row for 3 dB as: two sources at 90 and 87 dB combine to 90 + 1.76 = 91.76 dB, and the quieter one accounts for a third of the total energy. Beyond a 10 dB gap the addition is within the repeatability of most field measurements.

Mistakes that give the wrong total

  • Adding the decibel figures arithmetically. 85 + 85 is not 170. It is 88.01, because the energies add and the logarithm does not.
  • Averaging levels arithmetically. The mean of 90 and 70 dB is not 80 dB in energy terms - the energy average is 10 x log10((10^9 + 10^7)/2) = 87.03 dB, because the louder value dominates completely.
  • Using 10 log where 20 log belongs, or the reverse. Power-like quantities use 10 log; amplitude-like quantities use 20 log. Sound pressure level is already power-like and takes 10 log.
  • Combining coherent sources with this formula. Two speakers on the same signal interfere rather than add energetically, giving up to 6 dB in phase and deep cancellation out of phase.
  • Mixing weightings. A-weighted and unweighted levels are different quantities. Combine like with like, and only compare the total against a limit expressed in the same weighting.
  • Applying the distance correction indoors. Beyond the critical distance a room's reverberant field dominates and the level stops falling with distance in anything like the free-field way.
  • Combining levels measured at different positions. Every level in the sum must be what that source produces at the one position you care about.

Where decibel addition turns up

In live sound, it is the arithmetic behind array design. Doubling the number of cabinets in a stack adds 3 dB of level if the boxes are driven independently and their outputs are uncorrelated, but a properly coupled array in the frequency range where the boxes are close together relative to a wavelength behaves coherently and can gain up to 6 dB. Which regime you are in depends on frequency and spacing, which is why line arrays behave so differently at 100 Hz and 5 kHz. The speaker impedance calculator covers the electrical side of adding cabinets, and it is worth noting that doubling amplifier power also gains 3 dB - the same logarithm from a different cause.

In occupational hygiene, energy summation underlies the equivalent continuous level, Leq, which averages a fluctuating exposure by energy rather than by level. That is why a few loud moments dominate a shift average, and why a 3 dB exchange rate - halving the permitted time for every 3 dB - is the energy-consistent choice. Some regulators use a 5 dB exchange rate for historical reasons, which is not energy-consistent, so check which applies before converting anything.

In environmental acoustics, the same summation combines traffic, plant and rail contributions at a receptor, each first corrected for its own distance and screening. That is where the point-versus-line distinction earns its keep: a single machine spreads spherically at 6 dB per doubling, while a busy road behaves as a line at 3 dB per doubling, so a road stays audible much further away than its peak level would suggest.

And in studio work, it explains why a mix's level does not rise the way the track count suggests. Adding a second uncorrelated track raises the sum by 3 dB, a fourth by another 3, and so on - so a 32-track mix of similar-level uncorrelated material sits about 15 dB above one track, not 32 times higher. Correlated material, such as a doubled vocal, behaves quite differently and can add up to 6 dB.

Frequently asked questions

What do two 85 dB sources add up to?

88.01 dB, not 170 dB. Doubling the acoustic energy raises the level by 10 x log10(2) = 3.0103 dB, and that is true whatever the starting level - two 60 dB sources give 63.01 dB and two 110 dB sources give 113.01 dB. The result depends only on the number of sources and their relative levels, never on the absolute value.

Why does doubling sound only add 3 dB?

Because the decibel is a logarithm of a power ratio, and the logarithm of 2 is 0.30103. Multiply by 10 for the decibel convention and you get 3.0103 dB. Doubling again adds another 3 dB, so four sources are 6 dB up and eight are 9 dB up. The scale is built this way precisely because it compresses the enormous range of audible energies into manageable numbers.

How much does a quieter source add to a louder one?

Very little once the gap exceeds about 10 dB. A source 10 dB down adds 0.41 dB, one 15 dB down adds 0.14 dB, and one 20 dB down adds 0.04 dB. At equal levels it adds the full 3.01 dB, at 3 dB down it adds 1.76 dB and at 6 dB down 0.97 dB. This is why noise control effort belongs on the dominant source.

Is 3 dB a noticeable change?

Barely, on a steady sound heard on its own, though it is easy to hear as a direct comparison. A change of about 10 dB is conventionally described as a doubling or halving of loudness, which is a rule of thumb from loudness-scaling experiments rather than a physical constant. Ten decibels corresponds to ten times the acoustic energy, which is why energy and perceived loudness diverge so sharply.

How does sound level fall with distance?

A point source in free field loses 6.02 dB per doubling of distance, because intensity spreads over a sphere and falls as 1 over r squared. A line source such as a busy road loses only 3.01 dB per doubling, because the energy spreads over a cylinder. Both are geometric spreading alone; air absorption, ground effects and barriers subtract more, and indoors the reverberant field stops the decrease entirely beyond the critical distance.

Can I compare this total against an 85 dB workplace limit?

Only if every level you entered was already A-weighted, and only after accounting for exposure time. Occupational criteria are defined on A-weighted levels averaged over a shift, so an unweighted instantaneous total is a different quantity. Combine A-weighted levels to get an A-weighted total, then work out the time-weighted average before comparing against any limit.

Why do two speakers playing the same signal not add 3 dB?

Because they are coherent rather than independent. Coherent sources add in pressure, not in energy, so where the two arrivals are in phase the pressure doubles and the level rises 6.02 dB, and where they arrive in antiphase they cancel. The result is an interference pattern that varies with position and frequency. The 3 dB figure applies only to uncorrelated sources such as separate machines or separate instruments.

How do I subtract a background level from a measurement?

Convert both to energy, subtract, and convert back: L_source = 10 x log10(10^(L_total/10) − 10^(L_background/10)). If the total is 85 dB and the background is 80 dB, the source alone is 10 x log10(10^8.5 − 10^8) = 83.35 dB. When the total is less than about 3 dB above the background the subtraction becomes unreliable, and most measurement standards refuse to accept a correction at all below that margin.

References