Air Changes Per Hour (ACH) Calculator

Air changes per hour is airflow expressed as multiples of the room's own volume: 6 ACH means the fan moves six times the room's air volume every hour. This calculator works in both directions at once. Enter the room dimensions and the airflow you have, and it returns the resulting ACH and the minutes per nominal air change; enter a target ACH and it returns the airflow you need to hit it. Both answers appear together, so you can size a fan and check an existing one in the same pass.

Calculator

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Inputs this calculator takes, with typical values
InputWhat to enterExample
Room lengthInterior clear dimension of the space being ventilated.20 ft
Room widthThe second horizontal dimension of the space.15 ft
Ceiling heightFloor to ceiling; use the average height for a sloped or vaulted ceiling.8 ft
Airflow into or out of the roomMeasured or rated fan airflow; use the value at the actual static pressure, not the free-air rating.250 cfm
Target air changes per hourThe rate your code, standard or process specification calls for in this space.6 ACH

It returns

  • Air changes per hour delivered — The airflow you entered expressed as multiples of the room volume per hour.
  • Airflow needed for the target
  • Room volume
  • Minutes per nominal air change
  • Airflow surplus or deficit vs target

The formula

ACH=60QV
C(t)C(0)=eACHt

In plain text: ACH = Q x 60 / V ; Q_required = ACH_target x V / 60

  • ACHAir changes per hour (1/h)
  • QAirflow into or out of the space (cfm)
  • VRoom volume, length x width x height (cu ft)
  • 60Minutes per hour, converting cfm to cubic feet per hour (min/h)

In SI the 60 disappears: with airflow in cubic metres per hour and volume in cubic metres, ACH is simply the ratio of the two.

Updated Category Airflow, Fans & Ventilation Verified against published test cases Reading time 11 min

What an air change per hour actually measures

ACH normalises airflow by the size of the space it serves. Two hundred and fifty cfm is a lot of air in a bathroom and very little in a warehouse, so the raw airflow number tells you nothing on its own. Divide it by the room's own volume and you get a rate that is comparable between spaces: how many times per hour the fan moves a volume of air equal to the room's.

The arithmetic is a unit conversion. Airflow in cubic feet per minute, multiplied by 60, gives cubic feet per hour. Divide by the room volume in cubic feet and the cubic feet cancel, leaving a pure rate in reciprocal hours. In SI it is simpler still: cubic metres per hour divided by cubic metres, with no conversion constant at all.

What ACH does not measure is how much fresh air each person gets. That is a different question with a different answer, and it is the one modern ventilation standards mostly ask. ASHRAE 62.1 sets commercial ventilation rates from a per-person component plus a per-square-foot component, precisely because occupant-generated contaminants scale with people and material-generated contaminants scale with area, and neither scales with ceiling height. A room with a 20 ft ceiling gets a very generous ACH from a modest fan while its occupants get exactly the same fresh air as they would in an 8 ft room.

ACH remains the right measure when the contaminant is distributed through the volume rather than produced by occupants: dilution of solvent vapour in a shop, heat removal from a machine room, smoke clearance, or humidity control in a grow space. It is also the natural language for exhaust in small rooms, which is why bathroom and kitchen requirements are often written that way.

One air change does not replace the air

The phrase invites a picture of a piston pushing the old air out and pulling new air in. That is not what happens in a real room. Incoming air mixes with what is already there, and some of the newly supplied air leaves again before it has done any work.

For a perfectly mixed space with a contaminant that is not being replenished, the concentration decays exponentially: C(t)/C(0) = e−ACH·t with t in hours. After one nominal air change, e−1 = 0.368, so 37% of the original air is still there. Two air changes leave 13.5%, three leave 5.0%, and it takes about 4.6 air changes to reach 1%.

This matters whenever a clearance time is being specified. If a procedure requires 99% removal, that is 4.6 nominal air changes, not one: at 6 ACH the room needs 46 minutes, not 10. The minutes-per-change output on this page is the nominal figure, 60 divided by ACH, and it is the right number to multiply by the number of changes your requirement calls for.

Real rooms are also not perfectly mixed. Where the supply and the exhaust are close together, part of the airflow short-circuits between them and the effective rate in the occupied zone is lower than the nominal one. Where a room is long and the exhaust is at one end, the far end clears more slowly. Both effects mean the exponential model is the optimistic case, which is why standards that care about clearance specify diffuser placement as well as airflow.

Worked example: a 20 by 15 ft office at 250 cfm

An office measures 20 ft by 15 ft with an 8 ft ceiling, and the supply diffuser has been measured at 250 cfm with a flow hood. The design target for the space is 6 ACH.

  1. Volume. 20 × 15 × 8 = 2,400 cu ft.
  2. Delivered rate. 250 cfm × 60 min/h = 15,000 cu ft per hour. Divided by 2,400 cu ft: 6.25 ACH.
  3. Minutes per nominal change. 60 ÷ 6.25 = 9.6 minutes.
  4. Airflow the target needs. 6 × 2,400 ÷ 60 = 240 cfm.
  5. Surplus. 250 − 240 = +10 cfm, so the diffuser is delivering 4% more than the target.

Now check the clearance implication. If something is spilled in that office and you want 99% of it gone, that is 4.6 nominal changes at 9.6 minutes each, or about 44 minutes with the door shut and the fan running. If instead the requirement is 90% removal, that is 2.3 changes, or 22 minutes.

And check the ventilation implication. At 250 cfm this room is well ventilated by ACH, but if it seats eight people, the outdoor air component matters far more than the total supply. Only the outdoor fraction of that 250 cfm counts toward ASHRAE 62.1; the recirculated part dilutes nothing that the room itself is producing.

Choosing a target rate

Take the target from the document that governs the space, not from a general rule. Three families of requirement exist and they are written in different units.

Residential dwelling ventilation. ASHRAE 62.2 sets the whole-dwelling rate from floor area and the number of bedrooms, and it sets local exhaust separately: kitchens at 100 cfm intermittent or 5 ACH continuous, and bathrooms at 50 cfm intermittent or 20 cfm continuous. Note that only the kitchen figure is written as an ACH, and that the calculator's job there is simply to turn 5 ACH into a cfm for the kitchen's own volume.

Commercial ventilation. ASHRAE 62.1 uses a per-person plus per-area formula for outdoor air, not an ACH. If someone hands you an ACH figure for an office or a classroom, ask what it was derived from; it is usually a conversion of a 62.1 rate at an assumed ceiling height and occupancy, and it will be wrong for a room with a different height.

Process and hazard ventilation. This is where ACH is genuinely the governing unit: dilution ventilation for solvent vapour, battery rooms, refrigerant machinery rooms under ASHRAE 15, and similar. Those requirements come from the specific standard or from a mass-balance calculation on the contaminant generation rate, and they are the cases where a number like 12 or 20 ACH is meaningful rather than borrowed.

Once you have the airflow, the rest of the system follows. Size the duct that carries it with the duct size calculator, and check that the fan can actually deliver it against the pressure the duct imposes rather than at its free-air rating.

Airflow needed by room volume and target rate

Required airflow in cfm, computed as ACH x volume / 60.
Room volume (cu ft)4 ACH6 ACH8 ACH10 ACH12 ACH
50033506783100
1,00067100133167200
2,000133200267333400
4,000267400533667800
8,0005338001,0671,3331,600
12,0008001,2001,6002,0002,400

A 2,000 cu ft room is 250 sq ft at an 8 ft ceiling. Every value is linear in both volume and rate, so a room twice the size at the same rate needs twice the fan.

Where ACH calculations go wrong

  • Using a fan's free-air rating. A bathroom fan rated 80 cfm at 0.0 in.wg may deliver 45 cfm through a real duct with an elbow and a wall cap. Use the rating at 0.25 in.wg, which is the point HVI publishes for residential exhaust, or measure it.
  • Treating one air change as complete replacement. One nominal change leaves 37% of the original air in a perfectly mixed room. Multiply by the number of changes your clearance requirement actually implies.
  • Applying an ACH target to a tall room. ACH scales with ceiling height while occupant ventilation needs do not. A 20 ft ceiling makes any ACH target easy to hit and tells you nothing about the air the occupants are breathing.
  • Counting recirculated air as ventilation. Only outdoor air dilutes contaminants generated inside the room. A supply diffuser delivering 250 cfm of mostly recirculated air provides very little ventilation, whatever ACH it produces.
  • Ignoring where the air goes in and comes out. Supply and exhaust close together short-circuit, and the occupied zone sees less than the nominal rate. Rooms designed for clearance specify opening positions for this reason.
  • Forgetting makeup air. An exhaust fan can only move the air that something lets in. A 600 cfm range hood in a tight house will not deliver 600 cfm without a makeup air path, and it can depressurise the house enough to backdraft combustion appliances.

Which standard sets your rate

For dwellings, ASHRAE Standard 62.2 governs both the whole-house rate and local exhaust, and states kitchen continuous exhaust as 5 air changes per hour based on the kitchen volume. For commercial and institutional spaces, ASHRAE Standard 62.1 sets outdoor air from occupancy and floor area rather than from an air change rate. For refrigerating machinery rooms, ASHRAE Standard 15 sets ventilation from the refrigerant charge. Local mechanical codes adopt versions of these with amendments, so check the edition your jurisdiction has adopted before designing to a number.

ACH in load calculations and in blower-door work

The same quantity appears in two other places in HVAC, meaning slightly different things each time, and confusing them is common.

In a load calculation, the infiltration rate is quoted in natural ACH: the unintentional leakage through the envelope under normal wind and stack conditions. That figure multiplies into the 1.08 × CFM sensible term and the 0.68 × CFM latent term that drive the design loads, which is exactly how the Manual J load calculator uses it. A natural rate of 0.35 ACH is a typical current house.

In blower-door testing, the result is quoted as ACH50: air changes per hour with the house held at 50 pascals of pressure difference. That is a much larger number, because 50 Pa is far more pressure than weather normally supplies. Converting ACH50 to a natural rate divides by an LBL correlation factor that depends on climate, height and shielding, typically between about 17 and 20. Entering an ACH50 figure into a load calculation as if it were a natural rate overstates infiltration by roughly a factor of twenty.

In ventilation design, ACH is the delivered rate this calculator computes, and it counts only the air a fan actually moves. Keep the three apart: an envelope leakage rate, a pressurised test result, and a mechanical ventilation rate are three different measurements that share one unit. Once you have the mechanical rate, the airflow it implies is the same airflow that feeds the room CFM calculator and the pressure budget in the available static pressure calculator.

Frequently asked questions

How do I convert CFM to air changes per hour?

Multiply the airflow in cfm by 60 to get cubic feet per hour, then divide by the room volume in cubic feet. A 250 cfm supply in a 2,400 cu ft room is 250 x 60 / 2,400 = 6.25 ACH. Going the other way, required cfm equals the target ACH times the volume divided by 60. In metric the conversion vanishes: cubic metres per hour divided by cubic metres is already ACH.

How many air changes per hour do I need?

It depends on the space and on which standard governs it. ASHRAE 62.2 sets residential kitchen continuous exhaust at 5 ACH and bathrooms at a fixed cfm rather than an ACH. Commercial spaces under ASHRAE 62.1 are ventilated on a per-person and per-area basis, not on ACH at all. Process and hazard ventilation is where genuine ACH requirements live, and those come from the specific standard or a contaminant mass balance.

Does one air change replace all the air in a room?

No. In a perfectly mixed room, one nominal air change leaves 37% of the original air behind, because incoming and existing air blend continuously. Removal follows an exponential decay: two changes leave 13.5%, three leave 5%, and reaching 99% removal takes about 4.6 changes. Real rooms mix imperfectly, so those figures are the optimistic case.

What ACH does a bathroom fan give me?

Divide the fan's actual delivered airflow by the bathroom volume and multiply by 60. A 50 cfm fan in an 8 by 5 ft bathroom with an 8 ft ceiling, 320 cu ft, gives 9.4 ACH. The catch is that a fan rated 50 cfm at free air often delivers far less through a real duct and wall cap, so use the manufacturer's rating at 0.25 in.wg or measure it with a flow hood.

Is ACH the same as the ACH50 from a blower door test?

No, and confusing them is a large error. ACH50 is measured with the building held at 50 pascals, a pressure far above what weather produces. The natural infiltration rate used in load calculations is roughly ACH50 divided by an LBL factor of about 17 to 20, depending on climate zone, building height and wind shielding. A house at 3.0 ACH50 has a natural rate near 0.15 to 0.18 ACH.

Why does a tall room get a better ACH from the same fan?

It does not; it gets a worse one. ACH divides airflow by volume, and a taller room has a larger volume, so the same fan produces a lower ACH. The trap runs the other way: because a tall room needs more airflow to hit any ACH target, sizing a tall space to a borrowed ACH figure produces a much larger fan than the occupancy would justify. That is why occupant ventilation standards use floor area and people rather than volume.

Do I count supply air or exhaust air?

Count whichever is the smaller in a room that has both, because a room cannot exchange more air than the lesser of what enters and what leaves. In a room with mechanical exhaust and passive makeup, the exhaust rate governs, provided the makeup path is genuinely open. In a supply-only room, the supply governs and the air leaves through whatever gaps exist.

How long should I run a fan to clear a room?

Multiply the minutes-per-change figure by the number of changes your target removal implies: 2.3 changes for 90%, 3.0 for 95%, 4.6 for 99%. At 6 ACH each change is 10 minutes, so 99% clearance takes about 46 minutes. Add margin for imperfect mixing, particularly where the supply and exhaust openings are close together.

References

  • ANSI/ASHRAE Standard 62.2, Ventilation and Acceptable Indoor Air Quality in Residential Buildings — ASHRAE
  • ANSI/ASHRAE Standard 62.1, Ventilation for Acceptable Indoor Air Quality — ASHRAE
  • ASHRAE Handbook - Fundamentals, Chapter 16, Ventilation and Infiltration — ASHRAE
  • ANSI/ASHRAE Standard 15, Safety Standard for Refrigeration Systems — ASHRAE